SOLUTION: How can one fifthx − 2 = one thirdx + 8 be set up as a system of equations?
A 5y − 5x = −10
3y − 3x = 24
B 5y − 5x = −10
3y + 3x = 24
Algebra ->
Expressions-with-variables
-> SOLUTION: How can one fifthx − 2 = one thirdx + 8 be set up as a system of equations?
A 5y − 5x = −10
3y − 3x = 24
B 5y − 5x = −10
3y + 3x = 24
Log On
A
5y - 5x = -10 divide by 5 --> y - x = -2
3y - 3x = 24 divide by 3 --> y - x = 8
--> inconsistent, no solution.
B
5y - 5x = -10
3y + 3x = 24
----
y - x = -2
y + x = 8
------------------- Add
2y = 6
y = 3, x = 5
=========================
C
5y + x = -10
3y + x = 24
------------------ Subtract
2y = -34
etc.
==============================
D
5y - x = -10
3y - x = 24
---------------- Subtract
2y = -34
etc.