SOLUTION: Please help me solve this equation: {{{ 0=(2-sqrt(x))/(5x+1) }}} I had multiplied by the denominator over one on both sides. I then distributed zero through it which cancelled eve

Algebra ->  Square-cubic-other-roots -> SOLUTION: Please help me solve this equation: {{{ 0=(2-sqrt(x))/(5x+1) }}} I had multiplied by the denominator over one on both sides. I then distributed zero through it which cancelled eve      Log On


   

Question 985562: Please help me solve this equation: +0=%282-sqrt%28x%29%29%2F%285x%2B1%29+
I had multiplied by the denominator over one on both sides. I then distributed zero through it which cancelled everything out. This had left me with +0=2=sqrt%28x%29+ and now I think I can subtract the two and that puts me to +-2=-sqrt%28x%29+. So I can multiply by a negative one to get rid of the negatives, right? And then take the square root of both sides and it leaves me with +x=sqrt%282%29+?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
When you get to the last step and you have 2+=+sqrt%28x%29, you want to SQUARE both sides then you get 4 = x