SOLUTION: How do you write an equation in standard form that goes through the point (-4,3) and with a y-intercept of 0?

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Question 985204: How do you write an equation in standard form that goes through the point (-4,3)
and with a y-intercept of 0?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
given:
the line passes through the point (-4,3)
and with a y-intercept of 0; means the line will pass through origin (0,0)
so, firs we can find the equation of this line in slope-intercept form
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-4, 3) and (x2, y2) = (0, 0).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%280-3%29%2F%280--4%29+=+-0.75.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -0.75%2A-4+%2Bb+=+0. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=3--0.75%2A-4+=+0.

y=(-0.75)x + (0)

Your graph:



so, the equation of this line in slope-intercept form is y=-0.75x
the standard form for linear equations:
ax+%2B+by+=+c
so, we have 0.75x%2By=0