Question 985183: Miguel is now twice as old as Pauline. Five years ago Miguel was three times as old as Pauline. Find their present ages.
Answer by ikleyn(52794) (Show Source):
You can put this solution on YOUR website!
Let x be the Pauline's present age.
Then the Miguel's present age is 2x, in accordance with the condition.
Five years ago Miguel's age was (2x-5) and Pauline's age was (x-5).
In accordance with the condition, you have an equation
2x-5 = 3*(x-5).
Solve it step by step:
2x - 5 = 3x - 15,
-5 + 15 = 3x - 2x,
10 = x.
Thus Pauline's present age is 10 years.
Hence, Miguel's present age is 2*10 = 20 years.
|
|
|