SOLUTION: Find two consecutive odd integers such that 3 times first integer is 5 more than twice the second

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Question 985169: Find two consecutive odd integers such that 3 times first integer is 5 more than twice the second
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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x=first integer; x+2=second integer
3x-5=2(x+2)
3x-5=2x+4
x=9 ANSWER 1: The first integer is 9
x+2=9+2=11 ANSWER 2: The second integer is 11.