SOLUTION: At a pet shop there were 10 more dogs than cats. The shop sold 2 dogs and bought 2 cats. Now there are twice as many dogs than cats. How many cats does the shop have now?
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Question 985133: At a pet shop there were 10 more dogs than cats. The shop sold 2 dogs and bought 2 cats. Now there are twice as many dogs than cats. How many cats does the shop have now? Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
D=original number of dogs; C= original number of cats
.
D=C+10 Ten more dogs than cats
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D-2=2(C+2) Substitute for C
(C+10)-2=2(C+2)
C+8=2C+4
4=C The shop originally had 4 cats.
The shop bought two cats so:
4+2=6
ANSWER: The shop now has 6 cats.
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Original number of dogs:
D=C+10=4+10=14 The shop originally had 14 dogs.
The shop sold two dogs:
14-2=12 The shop now has 12 dogs.
12 dogs is twice as many as 6 cats.
