Question 985094: June has 10 more five-dollar bills than ten-dollar bills, and she has ninety-five dollars in all.
How many five dollar bills does she have?
Thank you.
Found 4 solutions by Alan3354, ikleyn, macston, MathLover1:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! June has 10 more five-dollar bills than ten-dollar bills, and she has ninety-five dollars in all.
How many five dollar bills does she have?
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Without the "10 more" $5's, she has $45 in an equal # of $5's and $10
--> $45/$15 = 3 of each
--> 3 $10's and 13 $5's
Answer by ikleyn(52833)  (Show Source):
You can put this solution on YOUR website!
Let x be the number of ten dollar bills June has.
Then the number of five dollar bills in her possession is x+10.
In total, June has 10x + 5(x+10) dollars, which is $95.
It gives you an equation
10x + 5(x+10) = 95.
Solve it step by step:
10x + 5x + 50 = 95,
15x = 95 -50,
15x = 45,
x =  = 5.
Hence, June has 5 10-dollar bills and 5 + 10 = 15 of 5-dollar bills.
Answer by macston(5194)  (Show Source):
You can put this solution on YOUR website! .
F=number of $5 bills; T=number of $10 bills=F-10
.
$5F+$10T=$95
$5F+$10(F-10)=$95
$5F+$10F-$100=$95
$15F=$195
F=13
ANSWER: She has 13 $5 bills.
Answer by MathLover1(20850)  (Show Source):
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