SOLUTION: 1. Solve the system of equations by elimination. 2x2 + 6y2 = 168 2x2 + y2 = 43 Options: (±3, ±5) (±5, ±3) (±3, ±3) (±5, ±5) 2. A box contains 4 white ribbons a

Algebra ->  Equations -> SOLUTION: 1. Solve the system of equations by elimination. 2x2 + 6y2 = 168 2x2 + y2 = 43 Options: (±3, ±5) (±5, ±3) (±3, ±3) (±5, ±5) 2. A box contains 4 white ribbons a      Log On


   



Question 984964: 1. Solve the system of equations by elimination.
2x2 + 6y2 = 168
2x2 + y2 = 43
Options:
(±3, ±5)
(±5, ±3)
(±3, ±3)
(±5, ±5)
2. A box contains 4 white ribbons and 8 pink ribbons. Determine whether the events of picking a white ribbon and then another white ribbon without replacement are independent or dependent. Then identify the indicated probability.
Options:
independent; 1/11
dependent; 1/12
dependent; 1/11
independent; 1/12
3. Each of 5 boys randomly chooses a watch from 12 different styles. What is the probability that at least 2 boys choose the same type of watch?
Options:
≈ 0.7387
≈ 0.6181
≈ 0.5387
≈ 0.3819

4. Use the standard deviation to identify any outliers in the given data set.
{3, 6, 30, 9, 10, 8, 5, 4}

Options:
3
8
30
none

5. Bill wants to plant roses in his triangular plot. There will be 1 plant at a corner. Each row will have 6 additional plants. He wants the plot to have as many rows as possible with 150 rose plants. How many rows will Bill's plot have?
Options:
5 rows
6 rows
7 rows
8 rows

























Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!

It is good that you placed only  5  problems in one request and not the entire textbook :)
In any case,  I will solve here for you only one problem,  namely,  the first one.

1.  Solve the system of equations by elimination

system%282x%5E2+%2B+6y%5E2+=+168%2C%0D%0A2x%5E2+%2B+y%5E2+=+43%29.

Distract the second equation from the first one  (this is the elimination step).  You will have

5y%5E2 = 168-43 = 125.

Hence,  y%5E2 = 125%2F5 = 25.
Therefore,  y = +/-5.

Now substitute the found value of  y  into the first system's equation.  You will get

2x%5E2 + 6%2A25 = 168,

2x%5E2 + 150 = 168,

2x%5E2 = 168 - 150 = 18.

x%5E2 = 18%2F2 = 9.

x = +/-3.

Answer.   x = +/-3, y = +/-5.