SOLUTION: What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation
y = ax^2 + bx + c
where a = 32, b = -29 and c = 108?
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-> SOLUTION: What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation
y = ax^2 + bx + c
where a = 32, b = -29 and c = 108?
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Question 984959: What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation
y = ax^2 + bx + c
where a = 32, b = -29 and c = 108? Found 2 solutions by josgarithmetic, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Put into standard form through completing the square, but do so completely in symbols from the given general form general form equation. Once done, read the variable expressions for coordinates of the vertex, and then substitute the given values.
Doing the symbolic process correctly, you should be able to form the equation, , or something equivalent.
You can put this solution on YOUR website! What is the x-coordinate, to 2 decimal places, of the vertex (i.e. turning point) of the parabola with equation
y = ax^2 + bx + c
where a = 32, b = -29 and c = 108?
You only need the values for a and b to calculate the value of the x-coordinate of the vertex
x-coordinate of vertex = , or , or , or 0.453125 ≈
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