SOLUTION: locomotive travels on a straight track at a constant speed of 40mph, then reverses direction and returns to its starting point, traveling at a constant speed of 60mph. A. What i

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: locomotive travels on a straight track at a constant speed of 40mph, then reverses direction and returns to its starting point, traveling at a constant speed of 60mph. A. What i      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 984940: locomotive travels on a straight track at a constant speed of 40mph, then reverses direction and returns to its starting point, traveling at a constant speed of 60mph.
A. What is the average velocity for the round trip?
B. What is the average speed for the round trip?
C. What is the total distance traveled by the train if the trip took 5 hours?
Please help, and Thank You!!!!

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!

First,  let us answer the third question:
>>> C. What is the total distance traveled by the train if the trip took  5  hours? <<<

Let  L  be the total distance.  Then you have the equation based on given data

L%2F40 + L%2F60 = 5.

Solve it by simplifying step by step:

3L%2F120 + 2L%2F120 = 5,

3L + 2L = 5*120,

5L = 5*120,

L = 120.

So,  the total distance is  120 miles.

Now, we can answer the second question:
>>> B. What is the average speed for the round trip? <<<

The round trip was  120 = 120 = 240 miles,  and it took 5 hours.
Hence,  the average speed for the round trip is  240%2F5 = 48 miles.

Finally,  the average velocity is  0,  since the the locomotive returned back to the starting point and the displacement is zero after  5 hours.

That is all.