SOLUTION: Container A and Container B had 50.36 liter of water.After 9.05 liter of water was transferred from container A to B,Container A had thrice as much water as container B.How much wa
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-> SOLUTION: Container A and Container B had 50.36 liter of water.After 9.05 liter of water was transferred from container A to B,Container A had thrice as much water as container B.How much wa
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Question 984921: Container A and Container B had 50.36 liter of water.After 9.05 liter of water was transferred from container A to B,Container A had thrice as much water as container B.How much water was in container A at first? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let a = original amt in container A
let b = original amt in container B
:
Write an equation for each statement
:
Container A and Container B had 50.36 liter of water.
a + b = 50.36
b = (50.36-a); use this form for substitution
:
After 9.05 liter of water was transferred from container A to B, Container A had thrice as much water as container B.
a - 9.05 = 3(b + 9.05)
a - 9.05 = 3b + 27.15
a = 3b + 27.15 + 9.05
a = 3b + 36.20
:
How much water was in container A at first?
Replace b with (50.36-a)) in the above equation
a = 3(50.36 - a) + 36.2
a = 151.08 - 3a + 36.2
a + 3a = 151.08 + 36.2
4a = 187.28
a = 187.28/4
a = 46.82 liters originally
