SOLUTION: a 48 inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece is 5 times as long as the first piece if x represent

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: a 48 inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece is 5 times as long as the first piece if x represent      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 984885: a 48 inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece is 5 times as long as the first piece if x represents the length of the first piece find the lengths of all three pieces
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
F=first piece; S=second piece=2F; T=third piece=5F
.
F+S+T=48 inches
F+2F+5F=48 inches
8F=48 inches
F=6 inches ANSWER 1: The first board is 6 inches.
S=2F=2(6in)=12in ANSWER 2: The second board is 12 inches.
T=5F=5(6in)=30in ANSWER 3: The third piece is 30 inches.
.
CHECK:
F+S+T=48 inches
6in+12in+30in=48 inches
48 inches=48 inches