SOLUTION: Need help with question please; Given; sin (x+y) = sin x cos y+ cos x sin y and cos (x +y) =cos x cos y - sin x sin y. Solve algebraically ; cos (x+90degrees) = 2 sin ^2 x - pi/2

Algebra ->  Trigonometry-basics -> SOLUTION: Need help with question please; Given; sin (x+y) = sin x cos y+ cos x sin y and cos (x +y) =cos x cos y - sin x sin y. Solve algebraically ; cos (x+90degrees) = 2 sin ^2 x - pi/2      Log On


   



Question 984824: Need help with question please; Given; sin (x+y) = sin x cos y+ cos x sin y and cos (x +y) =cos x cos y - sin x sin y. Solve algebraically ; cos (x+90degrees) = 2 sin ^2 x - pi/2 < x < pi/2.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


You should get used to using radians instead of degrees.







Use the unit circle to find the angle whose sine is negative 1/2 in the given interval. Negative angles are measured clockwise from the positive x-axis.



John

My calculator said it, I believe it, that settles it