SOLUTION: Find the area of the following triangle:
A=115°20', b=9.23m, c= 12.1m
(Round your answer to the nearest tenth of a square meter.)
Thanks
Algebra ->
Trigonometry-basics
-> SOLUTION: Find the area of the following triangle:
A=115°20', b=9.23m, c= 12.1m
(Round your answer to the nearest tenth of a square meter.)
Thanks
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Question 984762: Find the area of the following triangle:
A=115°20', b=9.23m, c= 12.1m
(Round your answer to the nearest tenth of a square meter.)
Thanks Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The area = (1/2)bc sin A, with two sides and an included angle.
sin 115.333=0.9038
A=(1/2)(0.9038)*9.23 m*12.1m
=50.5 m^2
