SOLUTION: A man travels 40 mph to his friends house. When he goes back on the same route he travels 45 mph. It was a four hour round-trip. How far did he travel

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Question 984733: A man travels 40 mph to his friends house. When he goes back on the same route he travels 45 mph. It was a four hour round-trip. How far did he travel
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website!

GOING r () d RETRG v () d Total t r=40,v=45,t=4 unknown variables: d

Basic uniform rates rule for travel, RT=D relating rate, time, distance. Use the idea to fill the missing time expressions.

GOING r d/r d RETRG v d/v d Total t

Equation from the data is .

STEPS TO SOLVE FOR d:

Substitute and evaluate.

Answer by MathTherapy(10553) (Show Source):
You can put this solution on YOUR website!

A man travels 40 mph to his friends house. When he goes back on the same route he travels 45 mph. It was a four hour round-trip. How far did he travel

Let distance, one-way, be D
Then time taken to travel on 1^st trip:
Time taken to travel on 2^nd trip:
Since round-trip took 4 hours, then we can say that:

-------- Multiplying by LCD, 360
17D = 1,440
D, or distance = , or miles