SOLUTION: O=5+7+9+11...+107
E=24+6+8+...+104
P=2+4+6+8...+106
without computing each sum,find which is greater O or E and by how many
without computing each sum, find which is greater O
Algebra ->
Probability-and-statistics
-> SOLUTION: O=5+7+9+11...+107
E=24+6+8+...+104
P=2+4+6+8...+106
without computing each sum,find which is greater O or E and by how many
without computing each sum, find which is greater O
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Question 984726: O=5+7+9+11...+107
E=24+6+8+...+104
P=2+4+6+8...+106
without computing each sum,find which is greater O or E and by how many
without computing each sum, find which is greater O or P and by how many Answer by solver91311(24713) (Show Source):
I presume E is really 2 + 4 + 6... instead of 24 + 6 + 8 ... like you wrote.
O has 107 - 5 = 102 divided by 2 = 51 plus 1 = 52 terms. Likewise, E has 52 terms. Each of the terms of O is 3 greater than the corresponding term of E, hence O is larger by 156. P is larger than E by the last term, namely 106, hence P is smaller than O by 156 minus 106 = 50.
John
My calculator said it, I believe it, that settles it
