SOLUTION: Please help me with this mixture word problem. A jewel has five rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add
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Question 98457This question is from textbook Algebra and Trigonometry
: Please help me with this mixture word problem. A jewel has five rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 75%. How much silver should he add? I'm having a lot of difficulty with setting up and equation for this particular problem. I would be very thankful if you would help me out. Thank you This question is from textbook Algebra and Trigonometry
You can put this solution on YOUR website! total weight of the rings = 18 * 5 = 90g
total amount of silver = 10/100 *90 = 9g
Total amount of gold in all the 5 rings = 90 -9 =81g
Let the amount of silver added be x grams
total weight of the mixture now = 90 + x
percentage of gold = 81/(90+x) *100
since the percentage of gold now is to be 75
81/(90+x) *100 = 75
81 * 100 = 75 (90+x)
27 * (3 * 25) * 4= 75(90+x)
canceling out 75 on both sided
27* 4 = 90 +x
x = 108 -90
=18g
