SOLUTION: Write the equation of the line (in slope-intercept form) of the line that is perpendicular to 3y= 7x - 4 and goes through (7,2).

Algebra ->  Linear-equations -> SOLUTION: Write the equation of the line (in slope-intercept form) of the line that is perpendicular to 3y= 7x - 4 and goes through (7,2).      Log On


   

Question 984510: Write the equation of the line (in slope-intercept form) of the line that is perpendicular to 3y= 7x - 4 and goes through (7,2).
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
The first thing you need to know is that the slopes of perpendicular lines are negative reciprocals. Let's find the slope of the given line
3y=+7x+-+4+
y+=+%287%2F3%29x+-+4%2F3.
The above equation is in the slope intercept form, so its slope is 7%2F3
The negative reciprocal is -3%2F7.
That is the slope of the line you are asked to find. So our equation is in the form
y+=+%28-3%2F7%29x++%2B+B where B is the intercept
You are told the line includes point (7,2).
Plug in that point and solve for B
2+=+%28-3%2A7%29%2F7+%2B+B+
2+=+-3+%2B+B
5+=+B
Plug that in and get y+=+-3x%2F7+%2B+5