SOLUTION: y= x-2/x^2 find dy/dx

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Question 984374: y= x-2/x^2 find dy/dx
Found 2 solutions by Alan3354, Boreal:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
y= x-2/x^2 find dy/dx
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y=+x-2%2Fx%5E2
y+=+x+-+2x%5E%28-2%29
y' = 1+%2B+4%2Fx%5E3

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
I will assume (x-2)/x^2
denominator is x^4
numerator is vdu-udv=x^2(x)-(x-2)(2x)
=(x^3-2x^2+4x)/x^4= (x^2-2x+4)/x^3. If this is set =0, complex roots, so no max or min.
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%28x-2%29%2Fx%5E2%29
If I assume x-(2/x^2)
dy/dx= 1+4x^(-3)
If this is set equal to zero,
4x^(-3)=-1; x^(-3)=(-1/4), x=-1/4^(1/3), or about -0.63=x
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cx-%282%2Fx%5E2%29%29