SOLUTION: Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the function gives a line with a

Algebra ->  Graphs -> SOLUTION: Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the function gives a line with a      Log On


   

Question 98396: Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the function gives a line with a slope of 0.09.
The monthly cost for 44 minutes of calls is $17.80. What is the monthly cost for 37 minutes of calls?






Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose that the monthly cost of a long-distance phone plan (in dollars) is a linear function of the total calling time (in minutes). When graphed, the function gives a line with a slope of 0.09.
The monthly cost for 44 minutes of calls is $17.80. What is the monthly cost for 37 minutes of calls?
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cost = (slope)minutes + (constant)
17.80 = 0.09(44)+ constant
constant = $13.84
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EQUATION:
cost = 0.09(minutes)+13.84
What is the monthly cost for 37 minutes of calls?
cost = 0.09(37) + 13.84
cost = 3.33 + 13.84
cost = $17.17
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Cheers,
Stan H.