SOLUTION: The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x? Is this right? X^2=4y^2 X=2y+1 (2y+1)^2=(2y)^2 2y+1=2y Why can

Algebra ->  Equations -> SOLUTION: The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x? Is this right? X^2=4y^2 X=2y+1 (2y+1)^2=(2y)^2 2y+1=2y Why can      Log On


   

Question 983928: The square of x is equal to 4 times the square of y. If x is 1 more than twice y, what is the value of x?
Is this right?
X^2=4y^2
X=2y+1
(2y+1)^2=(2y)^2
2y+1=2y
Why can't I take a square root of both side at this point?
The correct answer is 1/2.
Help would be greatly appreciated! Thanks a lot!
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
%282y%2B1%29%5E2=%282y%29%5E2
%282y%2B1%29%5E2-4y%5E2=0
The next steps will not involve square roots.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
x=2y%2B1
.
x%5E2=4y%5E2
x=2y OR x=-2y
2y%2B1=2y OR 2y%2B1=-2y
1=0 OR 4y%2B1=0 Since 1 does not equal 0:
4y=-1
y=-1%2F4
.
x=2y%2B1
x=2%28-1%2F4%29%2B1
x=%28-1%2F2%29%2B1
x=1%2F2
Remember to consider both positive and negative cases when taking square roots.