SOLUTION: Hi,
Farmer John is building a rectangular corral for cows. The railing that goes around the corral costs $8 per linear foot. Farmer John has decided that the length of the cor
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Farmer John is building a rectangular corral for cows. The railing that goes around the corral costs $8 per linear foot. Farmer John has decided that the length of the cor
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Question 983790: Hi,
Farmer John is building a rectangular corral for cows. The railing that goes around the corral costs $8 per linear foot. Farmer John has decided that the length of the corral will be twice as long as the width. Farmer John will also be purchasing cows to fill the corral to capacity. Each cow costs $800 and requires 20 sq feet of space.
Let w represent the width of the corral in feet.
a) write a simplified expression, in terms of w, for the number of cows farmer John can fit in the corral
20 ft squared/2w squared???
b) Write a simplified expression in terms of w for the amount of money Farmer John will spend on cows?
(20ft squared/2w squared)x $800 ???
c) Write a simplified expression in terms of w that expresses the amount of money Farmer Johns will spend on the corral and cows?
Thanks in advance. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
W=width in feet; L=length=2W; A=Area=(W)(2W)=
.
a) write a simplified expression, in terms of w, for the number of cows farmer John can fit in the corral:
20 ft squared/2w squared???
.
Total area/Area per cow=Number of cows =Number of cows
.
b) Write a simplified expression in terms of w for the amount of money Farmer John will spend on cows?
(20ft squared/2w squared)x $800 ???
.
Cost of cows=(number of cows)($800/cow)
Cost of cows=
.
c) Write a simplified expression in terms of w that expresses the amount of money Farmer Johns will spend on the corral and cows?
.
Perimeter=2(L+W)=2(2W+W)=6W
Cost of fence=$8P=$8(6W)=$48W
Cost of cows=$80W^2
Total cost=$80W^2+$48W=$16W(5W+3)
