SOLUTION: Please solve the equation for the interval [0, 2pi]: {{{tan^2(3x)=-tan(3x)}}} Thank you!

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Question 983737: Please solve the equation for the interval [0, 2pi]:
tan%5E2%283x%29=-tan%283x%29

Thank you!
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!








So



or






Use the Unit Circle to find the angles in the desired interval where the value of sin is zero. Divide each of these angles by 3.



Use the Unit Circle to find the angles in the desired interval where the magnitude of sin and cos is equal but the signs are opposite. Divide each of these angles by 3.



John

My calculator said it, I believe it, that settles it