Question 983734: Please solve the equation for the interval [ 0, 2pi ]:
Thank you!
Answer by ikleyn(52790)   (Show Source):
You can put this solution on YOUR website!
One solution is
 =  .
It gives  =  , where  is an arbitrary integer (k = 0, +/-1, +/-2, . . . ).
Hence  =  .
It gives for k = 0, 1, 2, 3
=  ,  =  ,  =  ,  =  .
Next, if is not zero, then you can reduce the original equation to the form
=  .
dividing it by  .
It gives you
= +/- +  , where is an arbitrary integer (k = 0, +/-1, +/-2, . . . ).
Hence = +/- +  .
It gives for k = 0, 1, 2, 3,
= ,  =  ,  ,  =  .
Answer. = , , , .
= , ,  , .
|
|
|
