SOLUTION: A waterfall has a height of 1300 ft. A pebble is thrown upward from the top of the falls with an initial velocity of 24 ft. Per second. The height, h, of the pebble after t seconds
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Question 983675: A waterfall has a height of 1300 ft. A pebble is thrown upward from the top of the falls with an initial velocity of 24 ft. Per second. The height, h, of the pebble after t seconds is given by the equation h=-16t^2 +24t+1300. How long after the pebble is thrown will it hit the ground? Answer by solver91311(24713) (Show Source):
That depends on whether it hits the ground at the top of the cliff where the waterfall starts or whether it hits the ground at the bottom of the falls.
In the first case, set and solve for the positive value of
In the second case, set and solve for the positive value of .
If you want an even more precise answer determine the height of the guy's hand when the pebble was released and add that to the left hand side of whichever equation that appropriately models the situation.
John
My calculator said it, I believe it, that settles it
