Question 983647: The perimeter of a rectangular building is 170 meters. The area is 1,624 square meters. What are the dimensions of the building?
Found 2 solutions by stanbon, Timnewman:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangular building is 170 meters. The area is
1,624 square meters. What are the dimensions of the building?
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L+W = 85
L*W = 1624
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Substitute for "W" and solve for "L"::
W = 85-L
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L(85-L) = 1624
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L^2 - 85L + 1624 = 0
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Positive solution:
Length = 29 meters ; Width = 85-29 = 56 meters
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Cheers,
Stan H.
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Answer by Timnewman(323)  (Show Source):
You can put this solution on YOUR website! hi,
Let L and w be the lenght and the width
if perimeter P of the bulding is 170m,therefore,
2(L+w)=170
then,
L+w=85----(1)
also, if the area is 1624m²,therefore,
L*w=1624----(2)
from (1)
L=85-w----(3)
put (3) in (2)
(85-w)w=1624
85w-w²=1624
w² -85w+1624=0
factorize the equation formed above and get;
(w-29)(w-56)=0
w=29 or w=56
put w=29 in (3)
L=85-29
L=56
put w=56 in (3)
L=85-56
L=29
From the above,the lenght L of the bulding is 56m and the width is 29m.
HOPE THIS HELPS;...
-------TIMNEWMAN------
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