SOLUTION: A shipment of 250 netbooks contains 3 defective units. Determine how many ways, and the probability, a vending company can buy three of these units and receive (a) no defective un

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Question 983635: A shipment of 250 netbooks contains 3 defective units. Determine how many ways, and the probability, a vending company can buy three of these units and receive
(a) no defective units.
(b) all defective units.
(c) at least one good unit.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A shipment of 250 netbooks contains 3 defective units.
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Binomial Problems with p(defective) = 3/250 ; p(good) = 247/250
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Determine how many ways, and the probability, a vending company can buy three of these units and receive
(a) no defective units.
# of ways:: 247C3 = 2481115 ways
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P(no defect) = 247C3/250C3 = 0.9643
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(b) all defective units.
# of ways:: 3C3 = 1
P(3 defective) = 1/250C3
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(c) at least one good unit.
# of total ways - # of ways with no defects = 250C3-247C3 = 91885
P(at least one defect) = 91885/250C3 = 0.0357
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Cheers,
Stan H.
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