SOLUTION: In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probablility of getting 3 yellow M&M's if 3 are taken at a time?
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-> SOLUTION: In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probablility of getting 3 yellow M&M's if 3 are taken at a time?
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Question 983578: In a sample bag of M&M's candy, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probablility of getting 3 yellow M&M's if 3 are taken at a time? Answer by solver91311(24713) (Show Source):
There are 20 total items, 6 of which are yellow. So, you have a probability of of the first item chosen being yellow. Then, given that the first one was yellow, the probability of the second one being yellow is because now you only have 5 yellow ones remaining out of only 19 total. Then, given that both the first and second ones were yellow, you have a probability that the third one is yellow of . The overall probability is the product of the probabilities of these three independent events.
John
My calculator said it, I believe it, that settles it
