SOLUTION: x1-x2+2x3=0 4x1+x2+2x3=1 x1+x2+x3=-1 gauss jordan elimination method

Algebra ->  Systems-of-equations -> SOLUTION: x1-x2+2x3=0 4x1+x2+2x3=1 x1+x2+x3=-1 gauss jordan elimination method      Log On


   



Question 983143: x1-x2+2x3=0
4x1+x2+2x3=1
x1+x2+x3=-1
gauss jordan elimination method

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%28matrix%283%2C4%2C%0D%0A1%2C-1%2C2%2C0%2C%0D%0A4%2C1%2C2%2C1%2C%0D%0A1%2C1%2C1%2C-1%29%29
Replace R2 with 4*R3-R2,
%28matrix%283%2C4%2C%0D%0A1%2C-1%2C2%2C0%2C%0D%0A0%2C3%2C2%2C-5%2C%0D%0A1%2C1%2C1%2C-1%29%29
Replace R3 with R3-R1,

Replace R3 with 2*R2-3*R3,
%28matrix%283%2C4%2C%0D%0A1%2C-1%2C2%2C0%2C%0D%0A0%2C3%2C2%2C-5%2C%0D%0A0%2C0%2C7%2C-7%29%29
Replace R2 with 7*R3-2*R2,

Replace R1 with 21*R1+R2,

Replace R1 with 6*R3-R1,

Divide R1 by (-21), R2 by 21, and R2 by 7.
%28matrix%283%2C4%2C%0D%0A1%2C0%2C0%2C1%2C%0D%0A0%2C1%2C0%2C-1%2C%0D%0A0%2C0%2C1%2C-1%29%29
So,
x%5B1%5D=1
x%5B2%5D=-1
x%5B3%5D=-1