SOLUTION: Two walls of a room are 4 yards long, and the other two are 5 yards long. The ceiling is 10 feet high. If it costs $.80 per square foot for plastering, find the cost of plastering

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: Two walls of a room are 4 yards long, and the other two are 5 yards long. The ceiling is 10 feet high. If it costs $.80 per square foot for plastering, find the cost of plastering       Log On

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Question 982754: Two walls of a room are 4 yards long, and the other two are 5 yards long. The ceiling is 10 feet high. If it costs $.80 per square foot for plastering, find the cost of plastering the walls and ceiling.
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
4*3*2=24ft
5*3*2=30ft
15*12=180 sqft ceiling
(24+30)*10=540 sqft walls
(180+540)(0.80=$576