SOLUTION: A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. For the half life: The half life is the soluti

Algebra ->  Rational-functions -> SOLUTION: A radio active isotope decays according to the exponential decay equation where t is in days. Round to the thousandths place. For the half life: The half life is the soluti      Log On


   



Question 982683: A radio active isotope decays according to the exponential decay equation where t is in days.
Round to the thousandths place.
For the half life: The half life is the solution (t) of the equation :
a/2=ae^−4.457t

Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
a/2=ae^−4.457t
Using a = 10 and a/2 = 5
a/2=ae^−4.457t
5 = 10 e^-4.457t
5/10 = e^4.457t
0.5 = e^-4.457t
ln0.5 = -4.457t ln e (ln e = 1)
ln 0.5 = -4.457t
t = ln 0.5/-4.457
t = 0.156 days
Hope this helps:-)