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Question 982581: I would very much appreciate your help with the following problem from a textbook. I am given a partial diagram of the function ax+by+12. The diagram shows a graph of a line with 2 coordinates (0,6) and (4,0) and I am asked to find the value of a and the value of b. From the coordinates I can determine the equation of the line is y=-3/2x+6 but for the life of me I do not know how to proceed. Help would be gratefully received.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I would very much appreciate your help with the following problem from a textbook. I am given a partial diagram of the function ax+by+12. The diagram shows a graph of a line with 2 coordinates (0,6) and (4,0) and I am asked to find the value of a and the value of b. From the coordinates I can determine the equation of the line is y=-3/2x+6 but for the life of me I do not know how to proceed. Help would be gratefully received.
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x/4 + y/6 = 1
6x + 4y -24 = 0
3x + 2y - 12 = 0
-3x - 2y + 12 = 0
a = -3 ; b = -2
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Using your formula::
y = (-3/2)x + 6
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Multiply thru by 2 to get:
2y = -3x + 12
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3x + 2y - 12 = 0
-3x - 2y + 12 = 0
a = -3 ; b = -2
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Cheers,
Stan H.
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