SOLUTION: Classify the graph of the following equation as a circle, a parabola, an ellipse, or a hyperbola. 9x^2 + 25y^2 −54x + 250y − 481 = 0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Classify the graph of the following equation as a circle, a parabola, an ellipse, or a hyperbola. 9x^2 + 25y^2 −54x + 250y − 481 = 0       Log On


   

Question 982552: Classify the graph of the following equation as a circle, a parabola, an ellipse, or a hyperbola.
9x^2 + 25y^2 −54x + 250y − 481 = 0
Answer by solver91311(24713) About Me  (Show Source):
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No term or no term: Parabola

and terms have the same coefficients: Circle

and terms have different coefficients but the same sign: Ellipse

and terms have different signs: Hyperbola

John

My calculator said it, I believe it, that settles it