Notice that I've changed the numbers, so you'll have to go
through it, using this as a model.  Yours is done EXACTLY 
the same way:
 
 
 
 
 
 
 
 
 
 
 
 
 ,
,  ,
,  
 
 
 
 
 
 
 Using the +, that's approximately 25.7358
Using the -, that's approximately 0.3497
However since there is ln(x-2) in the original equation, the
value of x-2 must be positive, or x > 2, so we may not use 
the minus sign.
Solution:
x = (6+e^3+sqrt(e^3(12+e^3)))}}}
Now use the above as a model and do your problem.
Edwin
Using the +, that's approximately 25.7358
Using the -, that's approximately 0.3497
However since there is ln(x-2) in the original equation, the
value of x-2 must be positive, or x > 2, so we may not use 
the minus sign.
Solution:
x = (6+e^3+sqrt(e^3(12+e^3)))}}}
Now use the above as a model and do your problem.
Edwin