SOLUTION: What is the sum of the infinite geometric series 3/4-9/16+27/64-81/256+ ..? A. 3 b. 1 C.3/4 D. 3/7

Algebra ->  Sequences-and-series -> SOLUTION: What is the sum of the infinite geometric series 3/4-9/16+27/64-81/256+ ..? A. 3 b. 1 C.3/4 D. 3/7      Log On


   



Question 982376: What is the sum of the infinite geometric series 3/4-9/16+27/64-81/256+ ..?
A. 3
b. 1
C.3/4
D. 3/7

Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
Instead of doing your problem for you, I will do one EXACTLY IN EVERY
DETAIL like yours, so that when you do yours, you can use this as a
model.

I will find the sum of this infinite geometric series instead:

2%2F3-4%2F9%2B8%2F27-16%2F81%2B%22%22-%22%22%2A%22%22%2A%22%22%2A%22%22

We should first check to see if it really is a geometric series, for sometimes
books contain errors/typos.  If it is a geometric series then this must be true:

matrix%281%2C2%2C2nd%2Cterm%29%2Fmatrix%281%2C2%2C1st%2Cterm%29%22%22=%22%22matrix%281%2C2%2C3rd%2Cterm%29%2Fmatrix%281%2C2%2C2nd%2Cterm%29%22%22=%22%22matrix%281%2C2%2C4th%2Cterm%29%2Fmatrix%281%2C2%2C3rd%2Cterm%29

So we calculate the three ratio to see if they are all equal:

matrix%281%2C2%2C2nd%2Cterm%29%2Fmatrix%281%2C2%2C1st%2Cterm%29%22%22=%22%22%28-4%2F9%29%2F%282%2F3%29%22%22=%22%22expr%28-4%2F9%29%2Aexpr%283%2F2%29%22%22=%22%22-12%2F18%22%22=%22%22-2%2F3

matrix%281%2C2%2C3rd%2Cterm%29%2Fmatrix%281%2C2%2C2nd%2Cterm%29%22%22=%22%22%288%2F27%29%2F%28-4%2F9%29%22%22=%22%22expr%288%2F27%29%2Aexpr%28-9%2F4%29%22%22=%22%22-72%2F108%22%22=%22%22-2%2F3

matrix%281%2C2%2C4th%2Cterm%29%2Fmatrix%281%2C2%2C3rd%2Cterm%29%22%22=%22%22%28-16%2F81%29%2F%288%2F27%29%22%22=%22%22expr%28-16%2F81%29%2Aexpr%2827%2F16%29%22%22=%22%22-432%2F1296%22%22=%22%22-2%2F3

They are all the same so it is a geometric series with common ratio = -2%2F3

It is a geometric series with a defined sum when taken to infinitely many
terms because the ratio r=-2%2F3 is greater than -1 and less than +1.

S%5Binfinity%5D%22%22=%22%22a%5B1%5D%2F%281-r%29, where a1 = 1st term = 2%2F3

S%5Binfinity%5D%22%22=%22%22%282%2F3%29%2F%281-%28-2%2F3%29%29%22%22=%22%22%282%2F3%29%2F%281%2B2%2F3%29%22%22=%22%22%282%2F3%29%2F%283%2F3%2B2%2F3%29%22%22=%22%22%282%2F3%29%2F%285%2F3%29%22%22=%22%22expr%282%2F3%29expr%283%2F5%29%22%22=%22%226%2F15=2%2F5

Answer to this problem = 2%2F5

Now do your problem EXACTLY the same way.

Edwin