SOLUTION: One number is 17 more than twice a second number. If three times the second number is subtracted from five time the first, the result is 9. Find the two numbers.
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: One number is 17 more than twice a second number. If three times the second number is subtracted from five time the first, the result is 9. Find the two numbers.
Log On
Question 982265: One number is 17 more than twice a second number. If three times the second number is subtracted from five time the first, the result is 9. Find the two numbers. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
F=first number; S=second number
.
F=2S+17
5F-3S=9 Substitute for F
5(2S+17)-3S=9
10S+85-3S=0
7S=-76
S=-(76/7)
.
F=2S+17
F=2(-76/7)+17
F=-152/7+119/7=-33/7
.
CHECK:
5F-3S=9
5(-33/7)-3(-76/7)=9
-165/7-(-228/7)=9
63/7=9
9=9
