SOLUTION: square root of 11(square root of 11 + x square root 22)
How do i do this kind of problem? I am lost it is
square root of 11 times square root of 11 plus x square root of
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-> SOLUTION: square root of 11(square root of 11 + x square root 22)
How do i do this kind of problem? I am lost it is
square root of 11 times square root of 11 plus x square root of
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Question 98208: square root of 11(square root of 11 + x square root 22)
How do i do this kind of problem? I am lost it is
square root of 11 times square root of 11 plus x square root of 22 Answer by bucky(2189) (Show Source):
You can put this solution on YOUR website! Given:
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This is a problem involving distributed multiplication. It is of the form:
. <=== call this rule 1
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Notice that you are just multiplying the term outside the parentheses by each of the terms
inside the parentheses.
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What makes this problem a little "different" is that it involves multiplication of square roots,
so you need to know a few rules about those multiplications. Here are a couple of rules for
square roots:
. <=== call this rule 2
.
and:
. <=== call this rule 3
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It seems as if this problem involves a lot of terms. But notice that there
is one term that is . If we apply rule 3 to that term, we can get a
from it by doing the following:
.
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So in the problem we can replace by and the problem
then becomes:
.
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Now let's apply rule 1. We'll do that by multiplying times each of the
terms in the parentheses to get:
.
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Now we can apply rule 2 to both of these terms. The first term is
and rule 2 tells us that the answer is just 11. So substituting 11 into the problem reduces
the problem to:
.
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Notice now that in the second term there is also a involved. Rule
2 also allows us to replace that product with 11. And this substitution further reduces the
problem to:
.
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That's the answer to this problem. I suppose that if you wanted to you could factor out
the 11 that is common to both terms to get but that's up to you
and what your instructions are.
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Hope this helps you to understand the problem a little more.