SOLUTION: An actress has to be on set, which is 21 miles away at 7am. If she wakes up at 5:30 am and does her make up for 48 minutes, how fast must she drive to get on to work on time? * ste
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: An actress has to be on set, which is 21 miles away at 7am. If she wakes up at 5:30 am and does her make up for 48 minutes, how fast must she drive to get on to work on time? * ste
Log On
Question 982009: An actress has to be on set, which is 21 miles away at 7am. If she wakes up at 5:30 am and does her make up for 48 minutes, how fast must she drive to get on to work on time? * step by step method please! THX! Found 2 solutions by jim_thompson5910, MathLover1:Answer by jim_thompson5910(35256) (Show Source):
The time difference from 6:18 am to 7:00 am is 42 minutes, which is 42/60 = 0.7 hrs
She must drive 21 miles for 0.7 hours
d = 21
r = unknown
t = 0.7
Use the equation d = r*t to solve for r
d = r*t
21 = r*0.7
21/0.7 = r*0.7/0.7 divide both sides by 0.7 to isolate r
30 = r
r = 30
She must drive at least 30 mph to make it on time. I put "at least" in there to mean that if she drives faster than 30 mph, then she'll have a bit of time to spare.
You can put this solution on YOUR website!
distance is:
time:
from to is
subtract the time she need for make up
so, to drive on set she has
since , we have
.........substitute for and for
so, she must drive to get on to work on time