SOLUTION: Red stones that sell for a $1.20/kg is mixed with blue stones that sell for $2.80/kg to make 200g of a mixed bag of stones that will sell for $250/kg. how many grams of each type o

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Red stones that sell for a $1.20/kg is mixed with blue stones that sell for $2.80/kg to make 200g of a mixed bag of stones that will sell for $250/kg. how many grams of each type o      Log On


   

Question 981994: Red stones that sell for a $1.20/kg is mixed with blue stones that sell for $2.80/kg to make 200g of a mixed bag of stones that will sell for $250/kg. how many grams of each type of stone were added to the bag?
Found 2 solutions by josgarithmetic, macston:
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Your decimal point is missing. You must mean, result of $2.50/kg.

Study this: http://www.algebra.com/my/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev.

You can instead, do the problem using just a single variable. Try that if you can. Easier.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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Problem below worked for value of mixed stones=$2.50/kg
No solution possible for $250/kg.(Must have added gold)
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R+B=0.2kg
R=0.2kg-B Use this to substitute for R below.
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$1.20/kg(R)+$2.80kg(B)=$2.50/kg(0.2kg) Substitute for R from above.
$1.20/kg(0.20kg-B)+$2.80/kg(B)=$0.50
$0.24-$1.20B+$2.80B=$0.50
$1.60B=$0.26
B=0.1625kg There were 162.5 g blue stones
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R=0.20kg-0.1625kg=0.0375kg There were 37.5 grams red stones.