SOLUTION: I have 3 more quarters than dimes, and 2 less nickels than dimes for a total of $3.45. How many coins of each type do I have?

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Question 981897: I have 3 more quarters than dimes, and 2 less nickels than dimes for a total of $3.45. How many coins of each type do I have?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
n = number of nickels
d = number of dimes
q = number of quarters

5n + 10d + 25q = 345
q = d + 3
n = d - 2

Write the equation in terms of d.

5(d - 2) + 10d + 25(d + 3) = 345
5d - 10 + 10d + 25d + 75 = 345
40d + 65 = 345
40d = 280
d = 7

There are 5 nickels, 7 dimes, and 10 quarters.