Question 981874: IN 10 years time a father will be twice as old as his daughter. 10 years he was six times as old as his daughter. How old is each now? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let fathers age now be x
daughters age now be y
10 years hence
(x+10)= 2(y+10)
x+10 = 2y+20
x-2y=10
10 years ago
(x-10)= 6(y-10)
x-10 = 6y-60
x-6y=-50
x-2y=10
x-6y=-50
subtract the equations
4y=60
y=15 daughter's age now
substitute y in x-2y=10
so x=40 present father's age
