SOLUTION: a scalene triangle with side b of (√3 -1) and side c of 5√2 has angle A which is 75 degrees. You are given that sin 75 degrees = √3 +1/2√2. Show that the ar

Algebra ->  Triangles -> SOLUTION: a scalene triangle with side b of (√3 -1) and side c of 5√2 has angle A which is 75 degrees. You are given that sin 75 degrees = √3 +1/2√2. Show that the ar      Log On


   

Question 981869: a scalene triangle with side b of (√3 -1) and side c of 5√2 has angle A which is 75 degrees. You are given that sin 75 degrees = √3 +1/2√2. Show that the area of the triangle is 2.5 cm squared.
my working out:1/2absinC
1/2 *5√2*(√3 -1*√3 +1/2√2
Answer by josgarithmetic(39631) About Me  (Show Source):
You can put this solution on YOUR website!
Your numeric sine of 75 degrees does not work as a possible sine value. I tried different groupings and the values are wrong.
... a web search just showed this: (sqrt(3)+1)/(2sqrt(2)) which rendered is %28sqrt%283%29%2B1%29%2F%282sqrt%282%29%29.

Not sure which side b or c you chose as the base. You might choose side b=sqrt%283%29-1 for the base; and then the triangle's height would be %285%2Asqrt%282%29%29 as the side c.

The height with these assignments would be %285sqrt%282%29%29sin%2875%29=5sqrt%282%29%28%28sqrt%283%29%2B1%29%2F%282sqrt%282%29%29%29, the height.

Putting all this into the area formula,
area is .

Do the arithmetic simplifications and see if you have the result you want/expect.