SOLUTION: My current age is 4 times what my sister's age was 20 years ago. I am now twice as old as I was 20 years ago. Ten years ago, my sister's age was 1/2 of my current age. Ten years ag

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Question 981839: My current age is 4 times what my sister's age was 20 years ago. I am now twice as old as I was 20 years ago. Ten years ago, my sister's age was 1/2 of my current age. Ten years ago, my age was 1.5 times my sister's age. What is my current age?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y, my age
x, my sister's age

My current age is 4 times what my sister's age was 20 years ago.
y=4%28x-20%29

I am now twice as old as I was 20 years ago.
highlight_green%28y=2%28y-20%29%29

Ten years ago, my sister's age was 1/2 of my current age.
x-10=%281%2F2%29y

Ten years ago, my age was 1.5 times my sister's age.
y-10=%281.5%29%28x-10%29


A few simple sentences forming a complicated description, but you should find that the
question to be answered will come from just one equation in the single variable, y.