SOLUTION: Which of the relations given by the following sets of ordered pairs is a function? {(1, 1), (1, 3), (1, 5), (1, 7), (1, 9)} {(-2, 1), (7, 5), (-4,0),(3,1),(0,-6)} {(

Algebra ->  Rational-functions -> SOLUTION: Which of the relations given by the following sets of ordered pairs is a function? {(1, 1), (1, 3), (1, 5), (1, 7), (1, 9)} {(-2, 1), (7, 5), (-4,0),(3,1),(0,-6)} {(      Log On


   

Question 981727: Which of the relations given by the following sets of ordered pairs is a function?

{(1, 1), (1, 3), (1, 5), (1, 7), (1, 9)}

{(-2, 1), (7, 5), (-4,0),(3,1),(0,-6)}

{(1,2),(2,3),(3,4), (3,3),(2,2),(1,1)}

{(2, -7), (6,5),(-3,9), (2,0), (-5,3)}
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
To be a function, there needs to be one unique
value of +y+ for every +x+
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The 1st set has 5 different values of +y+
for +x+=+1+ and violates definition
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The 2nd set is a function
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The 3rd set has
( 1,2 ) & ( 1,1 )
( 2,3 ) & ( 2,2 )
( 3,4 ) & ( 3,3 )
Each of these pairs violates the definition
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The 4th set has ( 2,-7 ) & ( 2,0 ) which
violate definition