SOLUTION: triangle ABC has the vertices at A(4, 2), B(-3, 6), and C(1, -3). Find the length of the median of the triangle drawn to the side BC.

Algebra ->  Length-and-distance -> SOLUTION: triangle ABC has the vertices at A(4, 2), B(-3, 6), and C(1, -3). Find the length of the median of the triangle drawn to the side BC.      Log On


   

Question 981551: triangle ABC has the vertices at A(4, 2), B(-3, 6), and C(1, -3). Find the length of the median of the triangle drawn to the side BC.
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
The median from BC to A
Midpoint of BC
(x1 + x2/2), (y1 = y2/2)
Using (-3, 6) (1, -3)
(-3 + 1/2 , (6 + (-3)/2)
(-2/2) , (3/2)
(-1, 3/2) Midpt
Distance from Midpt to A
Distance formula:
sqrt (x2 - x1)^2 + (y2 - y1)^2
Using (-1, 3/2) (4, 2)
sqrt (4-(-1))^2 + (2 - (3/2))^2
sqrt(5)^2 + (1/2)^2
sqrt 25 + 1/4
sqrt 101/4
= 25.3 units
Hope this helps:-)