SOLUTION: Three different non-zero digits are used to form six different three digit numbers. The sum of five of them is 3231. What is the sixth number?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Three different non-zero digits are used to form six different three digit numbers. The sum of five of them is 3231. What is the sixth number?      Log On


   



Question 981542: Three different non-zero digits are used to form six different three digit numbers. The sum of five of them is 3231. What is the sixth number?
Found 2 solutions by Edwin McCravy, greenestamps:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
567+576+657+675+756=3231.  The sixth number is 765

How did I get it? By deriving and solving the following 
Diophantine equation, which is a long process: 

122x + 212y + 221c = 3231

Edwin


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!
The only 3-digit number using those same three digits that is not shown in the given sum is 765, so that has to be the 6th number.