SOLUTION: 17% of students enrolled in higher education took at least 1 online course last fall. Choose 5 enrolled students at random. Find the probability that a. All 5 took online class

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Question 981332: 17% of students enrolled in higher education took at least 1 online course last fall. Choose 5
enrolled students at random. Find the probability that
a. All 5 took online classes.
b. None of the 5 took a course online
c. At least 1 took an online course.
d. At least 1 did not take any online course

Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website!
1. 0.17^5=0.000142 All did
2. 0.83^5=0.3939 None did
3. At least 1 is 1-P(none did)=0.6061
4. At least 1 did not take an online course is 1-P(All did)=1-0.000142=0.9999
Long way is
1 did not is .83*.17^4*5=0.003
2 did not is .83^2*.17^3*10 (the number of ways it can happen)=0.0339
3 did not is .83^3*.17^2*10=0.1653
4 did not is .83^4*.17*5=.4034
5 did not is .83^5=0.3939