Question 981319: x-y^2+6=0
2x^2+y^2-7-0
what are all possible (x,y) solutions?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! x-y^2+6=0
2x^2+y^2-7=0, editing
x=y^2-6;x^2=y^4-12y^2+36
substitute
2y^4-24y^2+72+y^2-7=0
2y^4-23y^2+65=0
(2y^2-13)(y^2-5)=0
2y^2=13
y^2=(13/2)
y= +/- sqrt (26)/2; after rationalizing the denominator
y^2=5
y= +/- sqrt (5)
first equation becomes
x-5+6=0; x+1=0, x=-1
x=-1; y=+/- sqrt (5); +/- sqrt (26)/2
second equation becomes
2+5-7=0 ; checks
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