SOLUTION: A colony of bacteria grows at an exponential rate according to the function,
P(t)=800e^{0.03t} , which describes the number of bacteria P at time t (in hours).
A) Find the
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-> SOLUTION: A colony of bacteria grows at an exponential rate according to the function,
P(t)=800e^{0.03t} , which describes the number of bacteria P at time t (in hours).
A) Find the
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Question 981314: A colony of bacteria grows at an exponential rate according to the function,
P(t)=800e^{0.03t} , which describes the number of bacteria P at time t (in hours).
A) Find the population after 12 hours. (Round your answer to the nearest whole number.)
B) When will the population double? (Round your answer to the nearest whole number.) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A colony of bacteria grows at an exponential rate according to the function,
P(t)=800e^{0.03t} , which describes the number of bacteria P at time t (in hours).
A) Find the population after 12 hours. (Round your answer to the nearest whole number.)
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P(t)=800e^{0.03t}
Sub 12 for t.
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B) When will the population double? (Round your answer to the nearest whole number.)
P(t)=800e^{0.03t}
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800e^{0.03t} = 2*800e^{0.03t}
Solve for t.
