SOLUTION: I need to convert from exponential to log: 2^x=3-t and 4^6t=(a+b)/a (0.8)^t=6.3 ...?! PLEASE HELP break this down for me they are all so different that basic form it seems I am

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I need to convert from exponential to log: 2^x=3-t and 4^6t=(a+b)/a (0.8)^t=6.3 ...?! PLEASE HELP break this down for me they are all so different that basic form it seems I am       Log On


   

Question 981197: I need to convert from exponential to log: 2^x=3-t
and 4^6t=(a+b)/a
(0.8)^t=6.3
...?! PLEASE HELP break this down for me they are all so different that basic form it seems I am SO lost.
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
This shows what the parts do:
y=b%5Ex, basic exponential equation model;
log%28b%2Cy%29=x, the logarithmic form.

Another way to understand:

antilog=%28base%29%5E%28logarithm%29


Exponential Form: 2%5Ex=3-t
-
log%282%2C%283-t%29%29=x, just a change of the form.


Exponential Form: 4%5E6t=%28a%2Bb%29%2Fa------???
You must mean this: 4%5E%286t%29=%28a%2Bb%29%2Fa
-
log%284%2C%28%28a%2Bb%29%2Fa%29%29=6t, changed to log form.


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Further comment:
A logarithm is an exponent.
The two equations log%28b%2Cy%29=x and y=b%5Ex are two equivalent equations.